find an two consecutive even numbers whose sum is 120
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Let two even consecutive number be x and x+2
x(x+2)=120
x^2+2x=120
x^2+2x-120=0
x^2+(12-10)x-120=0
x^2+12x-10x-120=0
x(x+12)-10(x+12)=0
(x+12)(x-10)
x=-12 or x=10
Always take positive number ,x=10
x+2=10+2=12
Therefore,10*12=120
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