Question

Find and correct the error in the mathematical statement 3x+x+4x=6x​

Answer 1

Step-by-step explanation:

x(3x+2)=3x2+2

c) 2x+3y=5xy2x+3y=5xy

d) x+2x+3x=5xx+2x+3x=5x

e) 5y+2y+y-7y=05y+2y+y−7y=0

f) 3x+2x=5x^23x+2x=5x2

g) \left(2x\right)^2+4\left(2x\right)+7=2x^2=8x+7(2x)2+4(2x)+7=2x2=8x+7

h) \left(2x\right)^2+5x=4x+5x=9x(2x)2+5x=4x+5x=9x

i) \left(3x+2\right)^2+3x^2+6x+4(3x+2)2+3x2+6x+4

Solution 1:

a) 4(x-5)=4x-5

Correction=

4\left(x-5\right)\ne4x-54(x−5)=4x−5

4\left(x-5\right)=\ 4x-204(x−5)= 4x−20

b) x\left(3x+2\right)=3x^2+2x(3x+2)=3x2+2

Correction= x\left(3x+2\right)\ne3x^2+3yx(3x+2)=3x2+3y

x\left(3x+2\right)=3^2+2xx(3x+2)=32+2x

c) 2x+3y=5xy2x+3y=5xy

Correction= x\left(3x+2\right)\ne3x^2+2xx(3x+2)=3x2+2x

2x+3y=2x+3y

d) x+2x+3x=5xx+2x+3x=5x

Correction= x+2x+3x\ne5xx+2x+3x=5x

x+2x+3x=6xx+2x+3x=6x

e) 5y+2y+y-7y=05y+2y+y−7y=0

Correction= 5y+2y+y-7y\ne05y+2y+y−7y=0

5y+2y+y-7y=8y-7y5y+2y+y−7y=8y−7y

f) 3x+2x=5x^23x+2x=5x2

Correction=

3x+2x\ne5x^23x+2x=5x2

3x+2x=5x3x+2x=5x

g) \left(2x\right)^2+4\left(2x\right)+7=2x^2=8x+7(2x)2+4(2x)+7=2x2=8x+7

Correction= \left(2x\right)^2+4\left(2x\right)+7=2x^2+8x+7(2x)2+4(2x)+7=2x2+8x+7

\left(2x\right)^2+4\left(2x\right)+7=4x^2+8x+7(2x)2+4(2x)+7=4x2+8x+7

h) \left(2x\right)^2+5x=4x+5x=9x(2x)

Answer 2

Answer:

x×2x×3x=6x^3

Step-by-step explanation:

(2×3)=6

x×x×x=x^3

then 6x^3

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