Find and correct the error of the mathematical statement ( − 4) 2 = 2 − 16 no spam
Answers
Answer:
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Answer:
) 4 (x-5) = 4x-5
Correction=
4\left(x-5\right)\ne4x-54(x−5)
=4 x−5
4\left(x-5\right)=\ 4x-204(x−5)= 4 x−20
b) x\left(3x+2\right)=3x^2+2x( 3 x+2)=3 x
2
+2
Correction= x\left(3x+2\right)\ne3x^2+3yx( 3 x+2)
=3 x
2
+3 y
x\left(3x+2\right)=3^2+2xx( 3 x+2)=3
2
+2 x
c) 2x + 3y = 5xy2 x+3 y=5xy
Correction= x\left(3x+2\right)\ne3x^2+2xx( 3 x+2)
=3 x
2
+2 x
2x + 3y = 2x + 3y
d) x+2x+3x=5xx+2 x+3 x=5x
Correction= x+2x+3x\ne5xx+2 x+3 x
=5x
x + 2x + 3x = 6xx+2 x+3 x=6x
e) 5y + 2y + y-7y = 05 y+2 y+Y−7 y=0
Correction= 5y + 2y + y-7y \ ne05 y+2 y+Y−7 y
=0
5y + 2y + y-7y = 8y-7y5 y+2 y+Y−7 y=8y−7 y
f) 3x+2x=5x^23 x+2 x=5x
2
Correction=
3x+2x\ne5x^23 x+2 x
=5x
2
3x+2x=5x3 x+2 x=5x
g) \left(2x\right)^2+4\left(2x\right)+7=2x^2=8x+7( 2 x )
2
+4( 2 x )+7=2 x
2
=8x+7
Correction= \left(2x\right)^2+4\left(2x\right)+7=2x^2+8x+7( 2 x )
2
+4( 2 x )+7=2 x
2
+8x+7
\left(2x\right)^2+4\left(2x\right)+7=4x^2+8x+7( 2 x )
2
+4( 2 x )+7=4 x
2
+8x+7
h) \left(2x\right)^2+5x=4x+5x=9x( 2 x )
2
+5x=4 x+5x=9 x
Correction= 2x^2+5x\ne4x+5x2 x
2
+5x
=4 x+5x
\left(2x\right)^2+5x=4x^2+5x( 2 x )
2
+5x=4 x
2
+5x
i) \left(3x+2\right)^2+3x^2+6x+4( 3 x+2)
2
+3 x
2
+6x+4
Correction: \left(3x+2\right)^2+3x^2+6x+4( 3 x+2)
2
+3 x
2
+6x+4
\left(3x+2\right)^2+9x^2+12x+4( 3 x+2)
2
+9 x
2
+12x+4