Math, asked by technohacker798, 10 days ago

Find and correct the errors in the following mathematical statement. Substituting x = −3 in (a) x^2 + 5x + 4 gives (−3)^2 + 5 (−3) + 4 = 9 + 2 + 4 = 15 (b) x^2 − 5x + 4 gives (−3)^2 − 5 (−3) + 4 = 9 − 15 + 4 = −2 (c) x^2 + 5x gives (−3)^2 + 5 (−3) = −9 − 15 = −24​

Answers

Answered by adityaray38970
1

Answer:

Solution:

An equation is a mathematical statement with an 'equal to' symbol between two algebraic expressions that have equal values.

a) x2+ 5x + 4 gives (-3)2 + 5(-3) + 4 = 9 + 2 + 4 = 15

For x = -3

L.H .S = x2 + 5x + 4

= (-3)2 + 5(-3) + 4

= 9 -15 + 4

= 13 -15

= -2

But RHS is given as 15

Thus, L.H.S ≠ R.H.S

The correct statement is x2+ 5x + 4 gives (-3)2 + 5(-3) + 4 = 9 -15 + 4 = -2

(b) x2 - 5x + 4 gives (-3)2 - 5(-3) + 4 = 9 - 15 + 4 = -2

For x = -3

x2 - 5x + 4

= (-3)2 - 5(-3) + 4

= 9 +15 + 4

= 28

But, RHS is given as -2

Thus, L.H.S ≠ R.H.S

The correct statement is x2 - 5x + 4 gives (-3)2 - 5(-3) + 4 = 9 + 15 + 4 = 28

(c) x2 + 5x gives (-3)2 + 5(-3) = - 9 - 15 = -24

For x = - 3

x2 + 5x

= (-3)2 + 5(-3)

= 9 -15

= - 6

But, RHS is given as -24

Thus, L.H.S ≠ R.H.S

The correct statement is x2 + 5x gives (-3)2 + 5(-3) = 9 - 15 = - 6

Answered by Tanveeriqbal
0

Answer:

Solution

verified

Verified by Toppr

(a) x

2

+5x+4=(−3)

2

+5(−3)+4=9−15+4=−2

(b) x

2

−5x+4=(−3)

2

−5(−3)+4=9+15+4=28

(c) x

2

+5x=(−3)

2

+5(−3)=9−15=−6

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