Math, asked by rajputparul1819, 7 months ago

Find and correct the errors in the statement: (3x + 2)^2 = 3x^2 + 6x + 4

Answers

Answered by charugarg3
0

Answer:

(a+b)^2=a^2+b^2+2ab

(3x+2)^2= (3x)^2+2^2+2*3x*2

= 9x^2+4+12x. (correct equation)

Answered by nikitasingh79
3

Given :  (3x + 2)² = 3x² + 6x + 4

 

Concept :  

Common errors we done by solving algebraical expression and equation:

Error 1

Coefficient 1 of a term is usually not written. So we often ignore that. But while adding like terms, we should include it in the sum.

Error 2

When we multiply the expression enclosed in a bracket by a constant (or a variable) outside, we usually applied the multiplication to the first term only. This is the wrong calculation. Each term of the expression has to be multiplied by the constant (or the variable).

Error 3

when we square a monomial, we usually ignored the numerical coefficient. This is the wrong method. The numerical coefficient and each factor has to be squared.

Error 4

when we square a binomial, we usually do not apply the proper identity. This is the wrong approach. The right identity should be used.

Error 5

While dividing a polynomial by a monomial, We usually don’t divide each term of the polynomial in the numerator by the monomial in the denominator.

 

Solution:

 We have : (3x + 2)² = 3x² + 6x + 4

LHS = (3x + 2)² = 9x² + 12x + 4

[(a + b)² = a² + b² + 2ab]

RHS = 3x² + 6x + 4

LHS ≠ RHS

 

Correct statement  :

(3x + 2)² = 9x² + 12x + 4                                

Hope this answer will help you….

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