find Angle A, Angle B, angle C, angles of a parallelogram ABCD if the angle between the altitudes from D to the side a b and b c is 60 degree as shown in the figure
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In triangle DAE, 60°+90°+angle DAE =180°
So,angle DAE = 30°
Now,angle DAE can also be written as angle A.
So, angle A=30°
Now angle C=angle A(opposite angles of a parallelogram are equal)
So, angle C=30°
Now angle C+angle D=180° {adjacent angles of a parallelogram are supplementary}
So angleD=150°
Now angle D=angle B( opposite angles of a parallelogram are equal)
So,angle DAE = 30°
Now,angle DAE can also be written as angle A.
So, angle A=30°
Now angle C=angle A(opposite angles of a parallelogram are equal)
So, angle C=30°
Now angle C+angle D=180° {adjacent angles of a parallelogram are supplementary}
So angleD=150°
Now angle D=angle B( opposite angles of a parallelogram are equal)
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