find angle abc.bac.acb
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Answer:
<BAC = 45°
<ACB = 70°
<ABC = 65°
Step-by-step explanation:
<BAC = EAF = 45° ( VERTICALLY OPP. ANGLES)
<ACB = 180 - 110 = 70 ( LINEAR PAIR)
<ABC = 180 - 45 - 70 = 65( ANGLES SUM PROPERTY OF ∆)
THANKS..
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