Question

find angle ABC in given figure​

Answer 1

Answer:

Since,BC is a diameter then

<CAB=90°. [angle in semicircle is equal to 90°]

<BAQ =60° (given)

By tangent property angle at the tangent is equal to an angle in alternate segment.Then,

<BAQ=<ACB=60°

In ∆ABC

sum of angles of a triangle is equal to 180°.

<ACB + <CAB + <ABC =180°

60° + 90° + <ABC =180°

150° + <ABC =180°

<ABC = 180° - 150°

<ABC = 30°

Please mark me as Brainlist