Question

find angle ABP mark you as a brainliest answer​

Answer 1

Answer:

50°

Step-by-step explanation:

OA = OB = Radius

⇒ ΔAOB is an isosceles triangle

Find∠OBA:

∠OBA = (180 - 100) ÷ 2

∠OBA = 40°

Line PQ is tangent to the circle

⇒ ∠OBP = 90°

Find ∠ABP:

∠ABP = 90 - 40 = 50°

Answer: 50°

Answer 2

B is tangent to the circle

angle OBP = 90

if point P and A are joined then

angle APB = 80

total angle of triangle OAB = 180

angle OAB and angle OBA should be equal so

100 + 2x = 180

x = 40

angle ABP is 90 - 40 =

50