Question

find angle ACB
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Find
find​

Answer 1

Answer:

In ∆BCD

Angle BDC= 100°

Angle BCD= 25°

Now, We know that, the sum of all the angles in a triangle is 180°

So, angle BDC+ angle BCD+ angle DBC = 180°

or, 100° +25° + angle DBC = 180

or, 125° + angle DBC. = 180°

or, angle DBC = 180° - 125°

or, angle DBC = 55°

Now, in ∆ ABC

angle ABC + angle BAC + angle ACB = 180°

or, 55° + 55°+ angle ACB = 180°

or, 110° + angle ACB = 180°

or, angle ACB = 180° - 110°

or, angle ACB = 70°

HOPE IT HELPS ☺️