Math, asked by RupeshBro, 9 months ago

Find angle ACB please soon as possible​

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Answered by Anonymous
22

Answer:

As in triangle ABC , AC= AB , So it is an isosceles. Hence , <B = <C

As , <A+<B+<C =180°, Therefore

80°+ 2<B = 180°

<B = 100°/2= 50°

Answered by SainaPaswan
6

In triangle, ACB

AC= AB this shows its a Isosceles traingle

as= Angle A + AngleB+ angleC

80°+ 2 AngleB=180°

AngleB = 100/2= 50°

Thanks..

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