find angle ACD BCD CDB
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it is given in question that ACD is perpendicular so
ACD =90
angle A + angle CDA + angle ACD = 360 degree
65+ 90+ angle ACD = 180 degree
angle ACD =360-65+90=25.
angle ACB = 90-25=75.
In∆ BCD
angle DCB+angle CDA+angle CBD=180
90+75+angle CBD=180
CBD=180-90+75=15
Here
we have
ACD=90
DCB=75
CBD=15
hope it help you
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