Math, asked by jit71, 11 months ago

find angle ACD BCD CDB ​

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Answers

Answered by jansi161977
0

Refer the attachment above for the answer

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Answered by jai5446
0

Answer:

it is given in question that ACD is perpendicular so

ACD =90

angle A + angle CDA + angle ACD = 360 degree

65+ 90+ angle ACD = 180 degree

angle ACD =360-65+90=25.

angle ACB = 90-25=75.

In∆ BCD

angle DCB+angle CDA+angle CBD=180

90+75+angle CBD=180

CBD=180-90+75=15

Here

we have

ACD=90

DCB=75

CBD=15

hope it help you

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