Find angle ADB
pls tell fast
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→ A, B and D are three points on a circle. A tangent, TA at A makes an angle x with the chord AB, i.e.<TAB = x. AD passes through the center of the circle. Therefore, ABD is a right-angled triangle with the right angle at B.
→ <TAD = 90 degrees [Radius or diameter of a circle makes a right angle with a tangent at the point of contact].
→ <TAB = x, or <BAD = 90 - x.
→ In triangle ADB, <ABD = 90, <BAD = 90-x.
→ So <ADB =180 -<ABD -<BAD =180–90-(90-x) = 180–90–90+x = 180–180+x
→ So, <ADB = x.
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<ADB =x.
Hope it helps.
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