find angle ADC BCD
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1
So,
ADC=180°-65°=
BCD=180°-75°=
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0
Answer:
Step-by-step explanation:
first it is cyclic quad.
there fore sum of opposite angle = 180°
angle ADC + angle ABC = 180°
ANGLE ADC + 65 = 180°
ADC = 180 - 65 = 115°
lly for DCB+BAD = 180
DCB + 75 = 180
DCB = 180 - 75
= 105°
AND ALSO SUM OF ALL ANGLE OF QUAD = 360°
∴ 75 + 65+ 105+115 = 360
I HOPE THIS WILL HELP U
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