find angle AED plz answer fast n correct
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it's very simple I think you
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Angle edc=31 degree
Angle dec=90-(31+31)
=28degree
Angle aeb =28 degree(opposite angles)
Let angle a and b=x
2x+28=90
2x=62
Angle a and angle b=31 degree each
Let angle aed and bec=y
28+28+y+y=360(full angle)
2y=360-56
2y=304
Y=152
Therefore angle aed=152 degrees
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