find angle AOC fast please
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AOC = 135°
Here it is m8,
In ∆ABC,
B = 90° &
A+C = 90° (By Angle Sum Property)
As A+C = 90°
That means,
OAC+OCA = 45°
Now, By Angle Sum Property,
AOC + (OAC+OCA) = 180°
AOC + 45° = 180°
AOC = 180°-45° = 135°
AOC = 135°
Hence Derived m8.
Thanks for asking this noob question,
Get Nonscoped.
Here it is m8,
In ∆ABC,
B = 90° &
A+C = 90° (By Angle Sum Property)
As A+C = 90°
That means,
OAC+OCA = 45°
Now, By Angle Sum Property,
AOC + (OAC+OCA) = 180°
AOC + 45° = 180°
AOC = 180°-45° = 135°
AOC = 135°
Hence Derived m8.
Thanks for asking this noob question,
Get Nonscoped.
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