Question

find angle AOC
in this figure plzzzz
​

Answer 1

Answer:

As AB is the straight line

angle AOC + angle COB = 180° ( linear pair )

( 3x + 5 )° + 55° = 180°

3x + 60° = 180°

3x = 180° - 60°

3x = 120°

$x = \frac{120}{ 3 } \\ x = 40$

so, angle AOC = ( 3x + 5 )°

= 3 × 40 + 5

= 120 + 5

= 125°

I hope it will help you

Answer 2

Step-by-step explanation:

angle BOC+AOC=180(by linear pair)

55+3×+5=180

55+5+3×=180

60+3×=180

3×=180-60

3×=120

×=120/3

×=40

therefore X = 40

angle AOC= 3x+5

= 3x40+5

=125