FIND ANGLE B from the picture
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HERE YOU GO~
In triangle BCD,
/_B + /_BDC + /_BCD = 180°
{ Angle sum property}
( All Angles in a triangle add up to 180° )
Therefore,
/_B + 100° + 25° = 180°
=> /_B + 125° = 180°
=> /_B = 180° - 125 °
.:. /_B = 55°
HOPE IT HELPS YOU......
THANKS.....
@anmol
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