Question

find angle B if tan (A+B) =1/ root 3 and sin A = 1/2​

Answer 1

∠B = ?

Tan (A+B) = 1/√3

Sin A = 1/2

Tan (A+B) = 1/√3

Tan (A+B) = Tan30° ( °.° Tan30°=1/√3)

(A+B) = 30------ (i)

Sin A = 1/2

Sin A = Sin 30° (°.° Sin 30°=1/2)

A = 30

Now, Put the value of A in eq.(i) ,

=> (A+B) = 30

=> A+B = 30

=> 30 + B = 30

=> B = 30 - 30

=> B = 0

Therefore , ∠B = 0