Question

Find angle B if tan(A-B)=1/
$\sqrt{3}$
and sinA=^3/2 also find cosB (A,B<90)




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Answer 1

Answer:

=> tan(A-B) = 1/√3

=> A-B = tan^-1(1/√3)

=> A-B = 30 degree.......... @1

=> Now, sinA = √3/2

=> A = 60 degree.

=> from equation 1

=> A - B = 30

=> 60 - B = 30

=> B = 30 degree.

so that cosB = cos30 = √3/2