find Angle B if tan (a-b) is equal to 1/ root 3 and sin A = root 3/2 and also find Cos B
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Hey !!!
tan ( a+b) = 1/√3
tan( a +b ) = tan30°
a+b = 30° --------1 )
and , sina = √3/2
sina = sin60°
a = 60° ------2 )
from equation 1 )
a - b = 30° [ but from equation 2 , a = 60°]
60° - b = 30°
-b = -30°
hence angle b = 30° Answer
hope it helps you !!!
@Rajujumar111
tan ( a+b) = 1/√3
tan( a +b ) = tan30°
a+b = 30° --------1 )
and , sina = √3/2
sina = sin60°
a = 60° ------2 )
from equation 1 )
a - b = 30° [ but from equation 2 , a = 60°]
60° - b = 30°
-b = -30°
hence angle b = 30° Answer
hope it helps you !!!
@Rajujumar111
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