find angle BAC in the given fig. if pq //rs
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Answer:
<BAC=43°
Step-by-step explanation:
<PAB=<CBA=87° (alternate int. angles)
<ACS+<ACB=180° (linear pair)
<ACB=180°-130°
<ACB=50°
In ∆ABC ,
<ABC+<ACB+<BAC=180° (angle sum property)
87°+50°+<BAC=180°
<BAC=180°-137°
<BAC=43°
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