Find angle BCP. If angle ABD = 60°
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As per figure, angle DCQ=40 degree
Angel ABD=60 degree
Construction, let us join the line CO,
Therefore, the angle becomes right angled (90 degree) at point C.
Therefore, in line QCP,
angle QCD+angle DCB+angle BCP=180 degree
40 degree +90 degree +angle BCP=180 degree
130 degrees + angle BCP=180 degrees
angle BCP=(180-130)degrees
angle BCP =50 degrees
Angel ABD=60 degree
Construction, let us join the line CO,
Therefore, the angle becomes right angled (90 degree) at point C.
Therefore, in line QCP,
angle QCD+angle DCB+angle BCP=180 degree
40 degree +90 degree +angle BCP=180 degree
130 degrees + angle BCP=180 degrees
angle BCP=(180-130)degrees
angle BCP =50 degrees
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