Find angle BDC, angle DBA and angle A
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<BDC+<BDA+<BCD=180(Co.int.of the same side)<BDC+<65°+50°=180 <BDC= 165° 165°+<BAD=180(Co.int.of the same side) <BAD=15° 65°+15°+<DBA=180(Angle sum property) <DBA=100°
opydomanpurp9tvu2:
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Answer:
angle BDC = 65°
angle DBA = 65°
angle A = 50°
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