Question

Find Angle BOC, CBO and EDO. (No wrong answers

Answer 1

Step-by-step explanation:

⊥ drawn from the center of the circle on chord bisects the chord

∴ angle BOD is 90° and out of that angle COD=38°

(i)∴angle BOC= angle BOD-COD

                    =90-38 =>52°

(ii) 0B and OC are radii ∴ OBC is an isosceles Δ

180( total sum of angles in Δ)= 52+x+x

180-52=2x

128/2=x

64=x

∴ angle COB =64°

(iii) angle EDO

180=90+38+y

180-128=y

58°=y

last one i am not sure but the ones on top are correct