Find angle C in any ∆ABC, if b = √2,c = √3, B = 45
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Answered by
5
b/c=√2/√3
sinB/sinC=√2/√3
sin45°/sinC=√2/√3
sinC=sin45°(√3)/√2
sinC=√3/√2
sinC=60°
Therefore, C=60°
sinB/sinC=√2/√3
sin45°/sinC=√2/√3
sinC=sin45°(√3)/√2
sinC=√3/√2
sinC=60°
Therefore, C=60°
Answered by
0
b/c=root 2/root 3
SinB/sin C=root 2/root 3
SinC=sin 45(root3)/roo2=root3/2
C=60
SinB/sin C=root 2/root 3
SinC=sin 45(root3)/roo2=root3/2
C=60
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