Question

find angle cbd pls????​

Answer 1

Answer:

20

Step-by-step explanation:

angle 2 = angle 1 ( vertically opposite angles )

1. In triangle CAP == angle 4 + angle 2 + angle 5 = 180 ( sum of all angle of triangle )

• 50 + 110 + angle 5 = 180
• angle 5 = 180 - 50 - 110
• angle 5 = 180 - 160 = 20

2. In triangle CAP and BPD

• angle 2 = angle 1 ( vertically opposite angles)
• PC = PD ( radius of circle )
• PA = PB ( radius of circle )

So triangle CAP =~ BPD ( SAS )

• angle 5 = angle 3 (C.P.C.T )
• 20 = angle 3

angle CBD = angle 3 = 20

Answer 2

Question:-

The value of <CBD or <5

Solution:-

Consider ∆PCA and ∆PDB

In both triangles

• CP = PB ( radii of Circle )
• AP = PD ( radii of Circle )
• <CPA = <DPB ( Vertically opposite angles )

So, ∆PCA =~ ∆ PDB

So, <CBD = <ACP (by CPCT)

So, <CBD = 50°