Math, asked by knsrivastav3074, 6 months ago

find angle cbd pls????​

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Answers

Answered by akadyan586
0

Answer:

20

Step-by-step explanation:

angle 2 = angle 1 ( vertically opposite angles )

  1. In triangle CAP == angle 4 + angle 2 + angle 5 = 180 ( sum of all angle of triangle )
  • 50 + 110 + angle 5 = 180
  • angle 5 = 180 - 50 - 110
  • angle 5 = 180 - 160 = 20

2. In triangle CAP and BPD

  • angle 2 = angle 1 ( vertically opposite angles)
  • PC = PD ( radius of circle )
  • PA = PB ( radius of circle )

So triangle CAP =~ BPD ( SAS )

  • angle 5 = angle 3 (C.P.C.T )
  • 20 = angle 3

angle CBD = angle 3 = 20

Answered by hemanthvadapalli123
0

Question:-

The value of <CBD or <5

Solution:-

Consider ∆PCA and ∆PDB

In both triangles

  • CP = PB ( radii of Circle )
  • AP = PD ( radii of Circle )
  • <CPA = <DPB ( Vertically opposite angles )

So, ∆PCA =~ ∆ PDB

So, <CBD = <ACP (by CPCT)

So, <CBD = 50°

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