find angle cbd pls????
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0
Answer:
20
Step-by-step explanation:
angle 2 = angle 1 ( vertically opposite angles )
- In triangle CAP == angle 4 + angle 2 + angle 5 = 180 ( sum of all angle of triangle )
- 50 + 110 + angle 5 = 180
- angle 5 = 180 - 50 - 110
- angle 5 = 180 - 160 = 20
2. In triangle CAP and BPD
- angle 2 = angle 1 ( vertically opposite angles)
- PC = PD ( radius of circle )
- PA = PB ( radius of circle )
So triangle CAP =~ BPD ( SAS )
- angle 5 = angle 3 (C.P.C.T )
- 20 = angle 3
angle CBD = angle 3 = 20
Answered by
0
Question:-
The value of <CBD or <5
Solution:-
Consider ∆PCA and ∆PDB
In both triangles
- CP = PB ( radii of Circle )
- AP = PD ( radii of Circle )
- <CPA = <DPB ( Vertically opposite angles )
So, ∆PCA =~ ∆ PDB
So, <CBD = <ACP (by CPCT)
So, <CBD = 50°
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