Question

find angle ced?? from Allen sample paper

Answer 1

OCI TRIANGLE
50°+90°+OCI=180°
OCI =40°
OCB ISOLATED TRIANGLE SO
OBC=OCI=40°
BOC=180°-80°=100°
AOB IS LINE
AOC+100°=180°
AOC=80°
AOC ISOLATED TRIANGLE
A ANGEL IS X C ANGLE ALSO X
2X+80°=180°
X=50°

B IS ANGLE BISECTOR WHOLE ANGLE 2*40°=80°
ABE TRIANGLE
80°+50°+ANGLE E=180°
E=50°