find angle DBC BDC and DBA
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Given:
ABCD is a ║gm.
∠ ADB = 65°
∠DBC = ∠ADB (∵AD ║ BC AND DB IS A TRANSVERSAL.)
∴∠DBC = 65°
∠BDC = ∠ADB (∵DIAGONALS OF A║GM BISECTS IT'S ANGLE.)
∠BDC = 65°
∠DBA = ∠BDC(∵INTERIOR ALTERNATE ANGLE
∠A = 180°-130°=50°
netra45:
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