FIND angle EDC FROM THE PICTURE
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2
Answer:
Angle EDC= 25°
Step-by-step explanation:
In triangle BCD
Angle BDC+Angle BCD+Angle DBC=180°
100°+25°+Angle DBC=180°
Angle DBC=180°-125°
Angle DBC=55°
DE||BC and AB is transversal
Angle DBC=Angle ADE
55°=Angle ADE (corresponding angle)
On line AB,
Angle ADE+Angle EDC+Angle BDC=180°(whole line is of 180°)
55°+Angle EDC+100°=180°
Angle EDC+155°=180°
Angle EDC=180°-155°
Angle EDC=25°
Thanks ask again.
Answered by
2
Answer:
angle BCD = angle EDC ( alt. int. angles)
25 degree = angle EDC
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