Math, asked by devendraarath, 10 months ago

FIND angle EDC FROM THE PICTURE ​

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Answered by pandeysp1975
2

Answer:

Angle EDC= 25°

Step-by-step explanation:

In triangle BCD

Angle BDC+Angle BCD+Angle DBC=180°

100°+25°+Angle DBC=180°

Angle DBC=180°-125°

Angle DBC=55°

DE||BC and AB is transversal

Angle DBC=Angle ADE

55°=Angle ADE (corresponding angle)

On line AB,

Angle ADE+Angle EDC+Angle BDC=180°(whole line is of 180°)

55°+Angle EDC+100°=180°

Angle EDC+155°=180°

Angle EDC=180°-155°

Angle EDC=25°

Thanks ask again.

Answered by Anonymous
2

Answer:

angle BCD = angle EDC ( alt. int. angles)

25 degree = angle EDC

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