Question

Find angle of ABC and angle of ACB in Fig.11.32​

Answer 1

hey mate,

= angle ACB=180-135 (linear pair )

=45degree

=angle ACB+ angle ABC+angle BAC=180 ,( angle sum property)

=45+70+angleABC=180

=115+angle ABC=180

= angle ABC= 65 degree

I hope it helps u

Answer 2

Given,

< BAC = 70°

< ACD = 135°

To find out,

The angles ABC and ACB.

Solution:

We know that,

An exterior angle of a triangle is equal to the sum of the opposite interior angles. 

< BAC + < ABC = < ACD

70° + x = 135°

x = 135° - 70°

x = 65°

Therefore the < ABC is 65°.

And Sum of all the angles in a triangle is equal to 180°

< BAC + < ABC + < ACB = 180°

70° + 65° + y = 180°

135° + y = 180°

y = 180° - 135°

y = 45°

Therefore the < ACB is 45°.

proof:

< BAC + < ABC + < ACB = 180°

70° + 65° + 45° = 180°

180° = 180°

L.H.S = R.H.S