Question

find angle of elevation
when an object at the top of a building of height 70 M is observed from a point on the ground 70 root 3 M away from the base of the building​

Answer 1

given

the height of building = 70

distance between the point and building = 70√3

angle of elevation =?

let it be x

by tan x = height of building /distance between them

tan x = 70/70√3

tan x = 1/√3

tan 30 = 1/√3

angle of elevation = 30degrees

Answer 2

Answer:

tanθ=Opposite/Adjacent

tanθ=70/70√3

tanθ=1/√3

teta= 30°

Step-by-step explanation: