find angle of elevation
when an object at the top of a building of height 70 M is observed from a point on the ground 70 root 3 M away from the base of the building
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Answered by
1
given
the height of building = 70
distance between the point and building = 70√3
angle of elevation =?
let it be x
by tan x = height of building /distance between them
tan x = 70/70√3
tan x = 1/√3
tan 30 = 1/√3
angle of elevation = 30degrees
the height of building = 70
distance between the point and building = 70√3
angle of elevation =?
let it be x
by tan x = height of building /distance between them
tan x = 70/70√3
tan x = 1/√3
tan 30 = 1/√3
angle of elevation = 30degrees
Answered by
2
Answer:
tanθ=Opposite/Adjacent
tanθ=70/70√3
tanθ=1/√3
teta= 30°
Step-by-step explanation:
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