find angle of inclination line passing through (3,√3) (0,0)
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Heya!!!
Let it's inclination be ©
Tan © = ( 0-√3 )/ (0-3)
Tan © = √3 / 3
Tan @ = √3 × √3 / 3√3
Tan © = 3 / 3√3
Tan © = 1/√3
Tan © = Tan 30°
© = 30°
So, it's inclination with x-axis is 30°
HAVE A G8 TYM.
Let it's inclination be ©
Tan © = ( 0-√3 )/ (0-3)
Tan © = √3 / 3
Tan @ = √3 × √3 / 3√3
Tan © = 3 / 3√3
Tan © = 1/√3
Tan © = Tan 30°
© = 30°
So, it's inclination with x-axis is 30°
HAVE A G8 TYM.
0robinsonrayer0:
how √3/3 become 3√3/3
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