find angle pqrst q=110 and s=130
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Given :
Angle PQR= 110°
Construction:
Extend a line PQ till RS.
Let the point be U.
So we got a triangle ∆ QRU.
Solution :
On Line PQU
We have an angle of 110°
Angle PQR + Angle RQU= 180° (because PQU is a straight line).
110° + Angle RQU= 180°
Angle RQU= 180°–110°
Angle RQU = 70°
Angle QUR = 180°-130°= 50° ( because they are alternate angles)
Angle QUR+Angle RQU+ Angle Angle QRU = 180 ° ( because of sum of all angkes of a triangle is 180°)
70°+ 50° + angle QRU= 180°
Angle QRU = 180°-120°= 60°
Angle QRU = 60°
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