Find angle TSQ in these figure
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Answer:
Given that
∠ TPS =40°.
and ∠ PRQ=80°.
as ∠PTS and angle PRS are corresponding angles so they must be equal hence
∠PTS=80°
Now in △PTS
Sum of all angles must be equals to 180°.
⟹ ∠PST=180°-120°(80+40)=60°
Also we know that ∠PTS + ∠TSQ =180°(as they both form linear)
So ∠TSQ=180°-60°
⟹ ∠TSQ=120°
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