.find angle x
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Answers
Answer:
a) 70+70+y = 180 (ASP property of triangle)
consider the 3 rd angle of the triangle as y
140+y=180
hence y= 180-140=40
x+y=180(supplementery angle)
x+40=180
hence x = 180-40=140
b)120+y =180
consider the 3 rd angle of the triangle as y
hence y = 180-120 = 60
x+y+70 =180 (ASP property of triangle)
x+60+70=180
x+130=180
hence x = 180-130 = 50
c) the other angle will be equal to x
2x+40 = 180
2x =180-40 = 140
hence x = 140/2
= 70
d) the other angle will be equal to x
2x+90 = 180
2x = 180-90 = 90
hence x = 90/2 =45
e) all sides are equal hence all the angles will be equal
hence 3x = 180
x = 180 /3 = 60
Note - Add the degree symbol by yourself
a) In ∆ ABC,
< A = 70° < B = 70° < C = y°
Now,
Sum of all angles of a ∆ = 180°
< A + < B + < C = 180°
70° + 70° + y° = 180°
140° + y° = 180°
y° = 180° - 140°
y° = 40°
Now,
y° + x° = 180° ( Supplementary angles )
40° + x° = 180°,
x° = 180° - 40°
Therefore, x° = 140°
b) In ∆ ABC,
< A = x° < B = 70° < C = y°
To find < C,
<ACB + <ACD = 180° (Supplementary angles)
y° + 120° = 180°
y° = 180° - 120°
Therefore, y° = 60°
Now,
Sum of all angles of a ∆ = 180°
< A + < B + < C = 180°
x° + 70° + 60° = 180°
x° + 130° = 180°
x° = 180° - 130°
Therefore, x = 50°
c) ∆ ABC is a isosceles ∆.
< A = 40° < B = x° < C = x°
( because 2 sides and angles are equal in isosceles ∆ )
Now,
Sum of all angles of a ∆ = 180°
< A + < B + < C = 180°
40° + x° + x° = 180°
2x° = 180° - 40°
2x° = 140°
Therefore, x° = 140° / 2°
= 70°
d) ∆ ABC is a right-angled isosceles ∆.
< A = 90° < B = x° < C = x°
( because 2 sides and angles are equal in isosceles ∆ )
Sum of all angles of a ∆ = 180°
< A + < B + < C = 180°
90° + x° + x° = 180°
2x° = 180° - 90°
2x° = 90°
Therefore, x° = 90° / 2°
= 45°
e) ∆ ABC is a equilateral ∆.
< A = x° < B = x° < C = x°
( because all the sides and angles are equal in equilateral ∆ )
Sum of all angles of a ∆ = 180°
< A + < B + < C = 180°
x° + x° + x° = 180°
3x° = 180°
Therefore, x° = 180° / 3°
= 60°
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