find angle x please urgent
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SakshiGouniyal:
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consider triangle ABC
40+60+angleACB=180(angle sum property)
angleACB=180-100
angleACB=80
angle ACB+x+angleDCE=180°(linear pair)
80+x+angleDCE=180
x+DCE=100
x=100°-angleDCE
x=40°(or)
AB||CD
AC is transversal
Then x=40°(alternate interior angles)
40+60+angleACB=180(angle sum property)
angleACB=180-100
angleACB=80
angle ACB+x+angleDCE=180°(linear pair)
80+x+angleDCE=180
x+DCE=100
x=100°-angleDCE
x=40°(or)
AB||CD
AC is transversal
Then x=40°(alternate interior angles)
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