Question

Find angle1, angle2, angle3,angle4 and angle5.​

Answer 1

Answer:

angle 5 =110° (vertically opposite angles)

angle 4+angle 5 + angle 2 + 110°=360°

angle 4+ angle 2 +110°+110°=360°

Since, angle 4 =angle 2 ( vertically opposite angles)

So, angle 4+angle 4=360°-220°

2angle4=140°

angle 4= 70° = angle 2

In ∆ABC,

angle 4+angle 3 +30°= 180°(angle sum property of triangle)

angle 3=180°-100°

angle 3=80°

In ∆ADE,

angle 2+ angle 1+ 60°=180°(angle sum property of triangle)

angle 1=180°-130°

angle 1=50°

Answer 2

Answer:

angle BAD = angle CAE (vertically opposite angle)

110=angle 5

angle BAD + angle DAE = 180

110 + angle DAE = 180

angle DAE= 180-110

angle DAE = 70

angle 2 = 70

angle BAC = angle DAE (vertically opposite angle)

angle 4 = 70

In ∆BAC

angle BAC + angle CBA + angle ACB= 180

70 + angle BAC + 30 = 180

angle BAC = 180-100

angle BAC = 80

angle 3 = 80

In ∆ADE

angle ADE + angle DAE + angle AED = 180

60 + 70 + angle 1 = 180

angle 1 = 180-130

angle 1 = 50

I hope it will help you