Question

find angles of a parallelogram in which angle A is equal to 2CB​

Answer 1

Correct option is

D

x=32, b=89 degrees, d=91 degrees

In ∥gm opposite angles are supplementary.

Therefore,

                 ∠B+∠D=180∘

             2x+25+3x−5=180∘

                     x=5180−20=32

    ∠B=2x+25=(2∗32)+25=89∘

    ∠D=3x−5=(3∗32)−5=91∘