Question

find angles ,X and y​

Answer 1

Answer:

In an equilateral ∆,

If one angle is of 90°

then the remaining two angles ata of equal measure.

Let that angles be x

180° - 90°= 2x

90° = 2x

90°/2 = x

45° = x

Angle RPQ + angle y = 180° ----(angles in linear pair are supplementary)

45° + y = 180°

y = 180° - 45°

y = 135°

Answer 2

Answer:

x=45° and y=135°

Step-by-step explanation:

given: PQ=QR  ; ∠PQR=90°

Solution:

∵PQ=QR

∴∠QPR=∠QRP    (angle opposite to equal sides are equal)

by angle sum property we know that

∠QPR+∠QRP+∠PQR=180°

2∠QRP+90°=180°  (∵∠QPR=∠QRP; ∠PQR=90°)

2∠QRP=90°

∠QRP=45°= x

also∠QPR=45°

Now as we can see that ∠QPR and ∠y forms linear pair

so,

∠QPR+∠y=180°

  ∠y=180°- ∠QPR

  ∠y=180°-45°

∠y=135°

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