Math, asked by ashagowdas10870, 5 months ago

find angles x and y. ​

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Answered by premudatha
1

Step-by-step explanation:

c. In the given figure,

ST=SU, Angle TSU = 92°

x+x+92°=180°

2x=180°-92°

2x=88°

x=88°/2

x=44°

Angle SUT = x=44°

Then 44°+y=180°

y=180°-44°

y=136°

d. Here also two angles are same i.e 40,40

y+40°+40°=180°

y+80°=180°

y=180°-80°

y=100°

And x=40°

Answered by rohitkaushik21
1

in 2nd: x=40°,y=100°

in 1st: x=44°,y=136°

in 1st:

as you know about the isosceles triangle property that angles opposite to equal sides are equal

so 40 +40+y=180

y=100°

and x=40°(voa)

in 2nd:

by triangle property angle X and linear pair of y is equal and angleTSU = 92 (BY VOA)

so x+x+92=180

x=44°

and 44+y=180

and y = 136°

so it is my very big effort please mark as brainliest

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