Question

find angles x and y ​

Answer 1

$\huge{\underline{\underline{\tt{QuesTion:}}}}$

Find the value of x and y.

$\huge{\underline{\underline{\tt{AnsWer:}}}}$

<92° = <S [Vertically opposite angles]

Let <T and <U be x because ∆STU is an isosceles triangle and angles opposite to equal sides are equal.

<T + <U + <S = 180° [Angle sum property]

x + x + 92° = 180°

2x = 180° - 92°

x = 88°/2

x = 44°

<U + y = 180° [Linear pair]

44° + y = 180°

y = 180° - 44°

y = 136°

Therefore, the value of x and y is 44° and 136° respectively.

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Answer 2

Answer:

$\huge \fbox \red{answer}$

Let <T and <U be x because ∆STU is an isosceles triangle and angles opposite to equal sides are equal.

<T + <U + <S = 180° [Angle sum property]

x + x + 92° = 180°

2x = 180° - 92°

x = 88°/2

x = 44°

<U + y = 180° [Linear pair]

44° + y = 180°

y = 180° - 44°

y = 136°

Therefore, the value of x and y is 44° and 136° respectively.