Question

find answer of this problem.​

Answer 1

As ABDC is a cyclic quadrilateral. And BDC is a isosceles triangle. The measure of angle d is 180-(30+30)=120 then A+D is 180.as it's cyclic. The measure of angle BAC is 180-120=60

Answer 2

arcAOC is semicircle

So, angleABC = 90°

In triangle BDC

BD=DC

so, angle DBC=angle DCB

= 30°

So, angle BDC+angle DBC+angle DCB=180°

angle BDC+60°=180°

angle BDC=120°

Now in cyclic quad ABCD,

angle BAC+ angle BDC=180°

angle BAC=180° -120°

angle BAC=60°

Hope this helps you. Please mark this as the brainliest answer.