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21) ABC is an equilateral ∆le of each side measure 2cm . calculate its area in m^2.
22) In an AP S5+S7= 167, S10=235 then find the AP where Sn denotes the sum of its first n terms ....
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Answers
Answer:
Step-by-step explanation:
Hi✌️✌️
21)Area of equilateral triangle = √3/4(a)²
√3/4(2)²
√3 m² is your answer..
18)
a)OA=a
OP=?
ANGLE BETWEEN TANGENTS=60°
Tangents are equally aligned to each other
=> <OPA=<OPB=30°
IN ∆OPA,
<POA=180°-90°-30°
=60°
Cos 60°=OA/OP
1/2 =a/OP
=> OP = 2a(Ans)
b)Since we have given that
Radius of small circle = 4 cm
Radius of large circle = 5 cm
So, we need to find the length of each chord of one circle which is tangent to the other circle.
Since it forms a right angle triangle.
So, it becomes,
H^2=B^2+p^2
5^2=4^2+B^2
25-16=b^2
B^2=9
B=3
So, Length of chord is given by
2B=2*3=6cm
Hence,the length of chord is 6cm
19)From the question we get that the a1= 2k, a2= k+10, a3= 3k+2 are in arithmetic progression so we know that if three consecutive terms are in A.P then we can write that b-a=c-b which is second term - first term = third term - second term.
Hence, on substituing the values from the question we will get that K+10 - 2k = 3k+2-(k+10).
K+10-2k =3k+2-k-10.
k -2k +10 = 3k-k +2-10.
-k +10= 2k -8.
2k+k= 10+8.
Which on solving we will get that the value of k will be.
k =18/3= 6.
Hence, k= 6.
And in the attachment there is Q-20 and Q-22
