Math, asked by ajit1012, 11 months ago

find anumber whose sixth part exceeds its nineth part by 1

Answers

Answered by Anonymous
0

i dont know ??????????????????

Answered by MonarkSingh
1
Here is your answer

Let the number be x

It's sixth part is x/6
and nineth part is x/9

ATQ
 \frac{x}{6}  -  \frac{x}{9}  = 1 \\  \frac{3x - 2x}{18}  = 1 \\ 3x - 2x = 1 \times 18 \\ x = 18
So the number is 18 Answer

Hope it helps you
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