Question

find any four solution for the following equation-4x+3y=12​

Answer 1

Answer:

$\huge\mathfrak{Solution:-}$

Given equation is 4x + 3y =12 

On putting x = 0 in Eq.

(i), we get 

4(0) +3y =12 ⇒ 3y =12

⇒ y = 12 / 3 = 4 

So, (0, 4) is a solution of given equation. 

On putting y = 0 in Eq.

(i), we get 

4x+ 3 (0) =12 ⇒ 4x =12

x = 12 / 4 =3

 So, (3, 0) is a solution of given equation.

 On putting x =1 in Eq. 

(i), we get  

4(1) + 3y=12  ⇒ 3y = 12 - 4 = 8 ⇒ y = 8 / 3 

So, (1,8 / 3) is another solution of the given equation. 

 Further, putting x = 2 in Eq.

(i), we get 

4(2) + 3y = 12 ⇒ 3y = 12 - 8 = 4 ⇒  y = 4 / 3 

So, (2, 4 / 3) is also a solution of the given equation.

Hence the four solutions of given equation are (0, 4), (3, 0), (1, 8 / 3) and (2,4 / 3). 

Answer 2

Step-by-step explanation:

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