Find any four solutions of the equation 4x + 3y = 12
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1.) Le, x=3, y=0
So,
4(3) + 3(0) = 12
12 + 0 = 12
2.) Let, x=0, y=4
So,
4(0) + 3(4) = 12
0 + 12 = 12
3.) Let, x=6, y=-4
So,
4(6) + 3(-4)
24 + (-12) = 12
24 - 12 = 12
4.) Let, x=12, y=-12
So,
4(12) + 3(-12) =12
48 + (-36) = 12
48 - 36 = 12
I hope this is helpful ☺
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