Question

Find, any three rational number between - 2
and o​

Answer 1

a=-2,b=0

n=3

d=

$\frac{b - a}{n + 1} = \frac{0 - ( - 2)}{3 + 1} = \frac{2}{4 } = \frac{1}{2} . \\ now \: subsitute \: the \: values \: in \: the \: form \: of \: a + d \: a + 2d \: a + 3d \\ = \frac{ - 3}{2 } \: - 1 \: \frac{ - 1}{2}$

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