find any two solution of equation 4x+3y=12
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4x+3y=12 4x+3y=12
put x=1 putx=2
4×1+3y=12 4×2+3y=12
4+3y=12 8+3y=12
3y=12-4 3y=12-8
3y=8 3y=4
y=8/3 y=4/3
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