find any two solution of the equation x-y+2=0
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Step-by-step explanation: x-y+2 = 0
x = y - 2 y = x - 2
square on both sides
x^2 = y^2 -4 - 2y
x^2 = x ^2 - 4 - 4x - 4 - 2(x-2)
x^2 = x^2 - 4 - 4x - 4 - 2x - 4
by transporting we get 4 + 4 + 4 = -6 x
x = -2 , y = -2 - 2 = - 4
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